5x^2-21x+16=0

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Solution for 5x^2-21x+16=0 equation:


Simplifying
5x2 + -21x + 16 = 0

Reorder the terms:
16 + -21x + 5x2 = 0

Solving
16 + -21x + 5x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(1 + -1x)(16 + -5x) = 0

Subproblem 1

Set the factor '(1 + -1x)' equal to zero and attempt to solve: Simplifying 1 + -1x = 0 Solving 1 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1x = 0 + -1 -1x = 0 + -1 Combine like terms: 0 + -1 = -1 -1x = -1 Divide each side by '-1'. x = 1 Simplifying x = 1

Subproblem 2

Set the factor '(16 + -5x)' equal to zero and attempt to solve: Simplifying 16 + -5x = 0 Solving 16 + -5x = 0 Move all terms containing x to the left, all other terms to the right. Add '-16' to each side of the equation. 16 + -16 + -5x = 0 + -16 Combine like terms: 16 + -16 = 0 0 + -5x = 0 + -16 -5x = 0 + -16 Combine like terms: 0 + -16 = -16 -5x = -16 Divide each side by '-5'. x = 3.2 Simplifying x = 3.2

Solution

x = {1, 3.2}

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